10x^2-16x-26=0

Solution for 10x^2-16x-26=0 equation:

10x^2-16x-26=0

a = 10; b = -16; c = -26;
Δ = b2-4ac
Δ = -162-4·10·(-26)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-36}{2*10}=\frac{-20}{20}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+36}{2*10}=\frac{52}{20}
=2+3/5
$